有序对的作用是存储两个值，并在之后根据需要再次提供

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PAIR = -> x { -> y { -> f { f[x][y] } } }
LEFT = -> p { p[ -> x{ -> y { x } }] }
RIGHT = -> p { p[ -> x{ -> y { y } }] }

(摘自《计算的本质，深入剖析程序和计算机 Understanding ComputationFrom Simple Machines to Impossible Programs》)

Python暴力通关

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class Solution(object):
    def maxSlidingWindow(self, nums, k):
        """
        :type nums: List[int]
        :type k: int
        :rtype: List[int]
        """
        ret = []
        length = len(nums)
        if 0 == length:
            return []
        w = length - k + 1
        for i in range(w):
            m = max(nums[i:i+k])
            ret.append(m)
        return ret

目录

• 熵和交叉熵 基础
• 相对熵 性质
• 证明一 Infomation inequality(信息不等性)
• 证明二 KL and maximum likelihood(极大似然估计相对熵最小)

挂他一科又何妨？

leetcode

leetcode

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